030_lesson#3
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ikrugloff wants to merge 1 commit into
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Dzhoker1
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Aug 30, 2018
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| # 1. В диапазоне натуральных чисел от 2 до 99 определить, сколько из них кратны любому из чисел в диапазоне от 2 до 9. | |||
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| # 2. Во втором массиве сохранить индексы четных элементов первого массива. Например, если дан массив со значениями 8, 3, 15, 6, 4, 2, то | |||
| print(arr[i], end=' ') | ||
| print() | ||
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| mn = min(arr) |
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Как не просил обойтись без min и `max, но всё равно все делают с ними )))
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| # 4. Определить, какое число в массиве встречается чаще всего. | |||
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Отлично. Я бы даже сказал, что это классика
| if arr[i] == arr[k]: | ||
| frq += 1 | ||
| if frq > max_frq: | ||
| max_frq = frq |
| index = -1 | ||
| while i < N: | ||
| if arr[i] < 0 and index == -1: | ||
| index = i |
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Так же нет стрелочек в блок-схеме. Впрочем, на оценку это не повлияет )))
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| # 6. В одномерном массиве найти сумму элементов, находящихся между минимальным и максимальным элементами. | |||
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| # 7. В одномерном массиве целых чисел определить два наименьших элемента. | |||
| s = 0 | ||
| print(f'{i} string:') | ||
| for j in range(M - 1): | ||
| n = int(input()) |
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Молчаливый input. Напомните озвучить всем на уроке, чтоб не делали такого )))
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| mx = -1 | ||
| for j in range(M): | ||
| mn = 200 |
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Если в 11 строке изменить диапазон (например дописать в конце + 300, то уже не будет работать.
Ответ будет на уроке )))
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Block-schemes:
https://drive.google.com/file/d/1yyVxEkRagoT2JX8j1JaWUFSuXF9Toigg/view?usp=sharing