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Longest_Substring.java
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100 lines (89 loc) · 2.7 KB
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/**
* Created by Administrator on 2016/5/9.
*/
public class Longest_Substring {
String str = new String();
public static void main(String args[]){
String S = new String();
Longest_Substring ss = new Longest_Substring();
String s = "abbccc";
S = ss.longestPalindrome(s);
System.out.print(S);
}
// public String longestPalindrome(String s) {
// int start = 0, end = 0;
// for (int i = 0; i < s.length(); i++) {
// int len1 = expandAroundCenter(s, i, i); //针对于 aba类型的字符串
// int len2 = expandAroundCenter(s, i, i + 1); //针对于 abba类型的字符串
//
// int len = Math.max(len1, len2);
// if (len > end - start) {
//
// start = i - (len - 1) / 2;
// end = i + len / 2;
// }
// }
// return s.substring(start, end + 1);
// }
//
// private int expandAroundCenter(String s, int left, int right) {
// int L = left, R = right; //中心算法,直接找中心点的对称来解决问题
// while (L >= 0 && R < s.length() && s.charAt(L) == s.charAt(R)) {
// L--;
// R++;
// }
// return R - L - 1;
// }
String longestPalindrome(String s) {
String S =Reverse(s);
int i= 0;
int j = 0;
int tmp = 0;
int local = 0;
int count = 0;
int temp = 0 ;
String max = new String();
int length = s.length();
char arr[] = s.toCharArray();
char arr1[] = S.toCharArray();
while(i<length)
{
local =i;
while(j<length)
{
tmp = j;
temp = 0;
while((i<length)&&(j<length)&&arr[i]==arr1[j]) //arr[i]==arr1[j]的判断放在前面的话,i,j会越界
{
i++;
j++;
temp++;
}
if(temp>count)
{
count = temp;
max = S.substring(tmp,j);
}
i = local;
j = tmp;
j++;
}
j = 0; // 内循环结束,需要进行初始化
i = local;
i++;
}
System.out.println(count);
return max;
}
String Reverse(String s){
char arr[] = s.toCharArray();
int j = arr.length;
for( int i=0;i<j;j--,i++)
{
char temp = arr[i];
arr[i] = arr[arr.length-1-i];
arr[arr.length-i-1] = temp;
}
return new String(arr); // 这里必须要用 new String(arr),不能用toString
}
}