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BinaryTreeLevelOrderTraversalII.java
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executable file
·54 lines (49 loc) · 1.47 KB
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/**
Given a binary tree, return the bottom-up level order traversal of its nodes' values. (ie, from left to right, level by level from leaf to root).
For example:
Given binary tree {3,9,20,#,#,15,7},
3
/ \
9 20
/ \
15 7
return its bottom-up level order traversal as:
[
[15,7],
[9,20],
[3]
]
confused what "{1,#,2,3}" means? > read more on how binary tree is serialized on OJ.
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*/
/**
* Definition for binary tree
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class BinaryTreeLevelOrderTraversalII {
public List<List<Integer>> levelOrderBottom(TreeNode root) {
List<List<Integer>> res = new LinkedList<>();
if (root == null) return res;
Queue<TreeNode> queue = new LinkedList<>();
queue.offer(root);
while (!queue.isEmpty()) {
List<TreeNode> buff = new LinkedList<>();
List<Integer> elem = new LinkedList<>();
while (!queue.isEmpty()) {
TreeNode node = queue.poll();
elem.add(node.val);
if (node.left != null) buff.add(node.left);
if (node.right != null) buff.add(node.right);
}
res.add(elem);
for (TreeNode node : buff) queue.offer(node);
}
Collections.reverse(res);
return res;
}
}