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GenerateAStringWithCharactersThatHaveOddCounts.java
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37 lines (34 loc) · 1.2 KB
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package leetcode;
/**
* GenerateAStringWithCharactersThatHaveOddCounts
* https://leetcode.cn/problems/generate-a-string-with-characters-that-have-odd-counts/
* 1374. 生成每种字符都是奇数个的字符串
* https://leetcode.cn/problems/generate-a-string-with-characters-that-have-odd-counts/solution/suanshu-by-oshdyr-9xp3/
*
* @author Tobin
* @since 2022-08-01
*/
public class GenerateAStringWithCharactersThatHaveOddCounts {
public static void main(String[] args) {
GenerateAStringWithCharactersThatHaveOddCounts sol = new GenerateAStringWithCharactersThatHaveOddCounts();
System.out.println(sol.generateTheString(7));
System.out.println(sol.generateTheString(4));
System.out.println(sol.generateTheString(2));
}
public String generateTheString(int n) {
StringBuilder sb = new StringBuilder();
if (n % 2 == 0) {
// 偶数, 拆成1+奇数
for (int i = 0; i < n - 1; i++) {
sb.append('a');
}
sb.append('b');
} else {
// 奇数
for (int i = 0; i < n; i++) {
sb.append('a');
}
}
return sb.toString();
}
}