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EvenOddTree.java
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115 lines (104 loc) · 3.59 KB
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package leetcode;
import utils.TreeNode;
import utils.Trees;
import java.util.Queue;
import java.util.concurrent.LinkedTransferQueue;
/**
* EvenOddTree
* https://leetcode-cn.com/problems/even-odd-tree/
* 1609. 奇偶树
* https://leetcode-cn.com/problems/even-odd-tree/solution/yan-du-you-xian-bian-li-by-oshdyr-mbsv/
*
* @author tobin
* @since 2021-12-25
*/
public class EvenOddTree {
public static void main(String[] args) {
EvenOddTree sol = new EvenOddTree();
TreeNode root = Trees.fromIntegers(new Integer[]{
1,
10, 4,
3, null, 7, 9,
12, 8, 6, null, null, 2});
System.out.println(sol.isEvenOddTree(root));
}
public boolean isEvenOddTree(TreeNode root) {
if (root == null) {
return false;
}
Queue<TreeNode> evenFloor = new LinkedTransferQueue<>();
Queue<TreeNode> oddFloor = new LinkedTransferQueue<>();
evenFloor.add(root);
int currFloor = 0;
while (!evenFloor.isEmpty() || !oddFloor.isEmpty()) {
if (currFloor % 2 == 0) { // 偶数层
TreeNode last = evenFloor.poll();
if (last.val % 2 != 1) {
// 非奇数即错误
return false;
}
while (!evenFloor.isEmpty()) {
// 偶数层的下层即奇数层
if (last.left != null) {
oddFloor.add(last.left);
}
if (last.right != null) {
oddFloor.add(last.right);
}
TreeNode curr = evenFloor.poll();
if (curr.val % 2 != 1) {
// 非奇数即错误
return false;
}
if (curr.val <= last.val) {
// 非严格递增即错误
return false;
}
last = curr;
}
// 偶数层的下层即奇数层
if (last.left != null) {
oddFloor.add(last.left);
}
if (last.right != null) {
oddFloor.add(last.right);
}
} else { // 奇数层
TreeNode last = oddFloor.poll();
if (last.val % 2 != 0) {
// 非偶数即错误
return false;
}
while (!oddFloor.isEmpty()) {
// 奇数层的下层即偶数层
if (last.left != null) {
evenFloor.add(last.left);
}
if (last.right != null) {
evenFloor.add(last.right);
}
TreeNode curr = oddFloor.poll();
if (curr.val % 2 != 0) {
// 非偶数即错误
return false;
}
if (curr.val >= last.val) {
// 非严格递减即错误
return false;
}
last = curr;
}
// 奇数层的下层即偶数层
if (last.left != null) {
evenFloor.add(last.left);
}
if (last.right != null) {
evenFloor.add(last.right);
}
}
// 累计层数
currFloor++;
}
return true;
}
}