Incorrect comment

[kaninaba94]

https://doc.rust-lang.org/rust-by-example/fn/closures/closure_examples/iter_find.html

fn main() {
    let vec1 = vec![1, 2, 3];
    let vec2 = vec![4, 5, 6];

    // `iter()` for vecs yields `&i32`.
    let mut iter = vec1.iter();
    // `into_iter()` for vecs yields `i32`.
    let mut into_iter = vec2.into_iter();

    // `iter()` for vecs yields `&i32`, and we want to reference one of its
    // items, so we have to destructure `&&i32` to `i32`
    println!("Find 2 in vec1: {:?}", iter     .find(|&&x| x == 2));
    // `into_iter()` for vecs yields `i32`, and we want to reference one of
    // its items, so we have to destructure `&i32` to `i32`
    println!("Find 2 in vec2: {:?}", into_iter.find(| &x| x == 2));

    let array1 = [1, 2, 3];
    let array2 = [4, 5, 6];

    // `iter()` for arrays yields `&&i32`
    println!("Find 2 in array1: {:?}", array1.iter()     .find(|&&x| x == 2));
    // `into_iter()` for arrays yields `&i32`
    println!("Find 2 in array2: {:?}", array2.into_iter().find(|&x| x == 2));
}

The comments here are confusing. I don't think they explain matters correctly. If iter() yields &i32 and &&i32 respectively for vectors and arrays, the arguments should be destructured differently in the closure args between the two types.