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389_find_the_difference.py
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54 lines (46 loc) · 1.73 KB
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# Solution 1
class Solution:
def findTheDifference(self, s: str, t: str) -> str:
ch_dict = {}
for i in range(len(t)):
if t[i] not in ch_dict:
ch_dict[t[i]] = 1
else:
ch_dict[t[i]] += 1
ans = ''
for i in range(len(s)):
if s[i] in ch_dict:
if ch_dict[s[i]] == 1:
del ch_dict[s[i]]
else:
ch_dict[s[i]] -= 1
else:
ans = s[i]
break
else:
ans = list(ch_dict.keys())[0]
return ans
# Solution 2
class Solution:
def findTheDifference(self, s: str, t: str) -> str:
sum1 = sum2 = 0
for i in range(len(s)):
sum1 += ord(s[i])
for i in range(len(t)):
sum2 += ord(t[i])
return chr(sum2 - sum1)
'''
This is my personal record of solving Leetcode Problems.
If you have any questions, please discuss them in [Issues](https://github.com/mengxinayan/leetcode/issues).
Copyright (C) 2020-2022 mengxinayan
This program is free software: you can redistribute it and/or modify
it under the terms of the GNU General Public License as published by
the Free Software Foundation, either version 3 of the License, or
(at your option) any later version.
This program is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
GNU General Public License for more details.
You should have received a copy of the GNU General Public License
along with this program. If not, see <http://www.gnu.org/licenses/>.
'''