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151_reverse_words_in_a_string.py
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30 lines (26 loc) · 1.17 KB
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class Solution:
def reverseWords(self, s: str) -> str:
string = s.strip(' ')
string_arr = string.split(' ')
string_arr.reverse()
ans = ''
for tmp_str in string_arr:
if tmp_str != '':
ans += tmp_str + ' '
ans = ans[:len(ans)-1]
return ans
'''
This is my personal record of solving Leetcode Problems.
If you have any questions, please discuss them in [Issues](https://github.com/mengxinayan/leetcode/issues).
Copyright (C) 2020-2022 mengxinayan
This program is free software: you can redistribute it and/or modify
it under the terms of the GNU General Public License as published by
the Free Software Foundation, either version 3 of the License, or
(at your option) any later version.
This program is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
GNU General Public License for more details.
You should have received a copy of the GNU General Public License
along with this program. If not, see <http://www.gnu.org/licenses/>.
'''