-
Notifications
You must be signed in to change notification settings - Fork 0
Expand file tree
/
Copy path14_longest_common_prefix.py
More file actions
41 lines (37 loc) · 1.46 KB
/
14_longest_common_prefix.py
File metadata and controls
41 lines (37 loc) · 1.46 KB
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
class Solution:
def longestCommonPrefix(self, strs: List[str]) -> str:
if len(strs) == 0:
return ''
if len(strs) == 1:
return strs[0]
lens = []
for i in range(len(strs)):
lens.append(len(strs[i]))
minlen = min(lens)
ans = ''
for i in range(minlen):
ch = strs[0][i]
flag = True
for j in range(1, len(strs)):
if ch != strs[j][i]:
flag = False
if flag == True:
ans += ch
else:
break
return ans
'''
This is my personal record of solving Leetcode Problems.
If you have any questions, please discuss them in [Issues](https://github.com/mengxinayan/leetcode/issues).
Copyright (C) 2020-2022 mengxinayan
This program is free software: you can redistribute it and/or modify
it under the terms of the GNU General Public License as published by
the Free Software Foundation, either version 3 of the License, or
(at your option) any later version.
This program is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
GNU General Public License for more details.
You should have received a copy of the GNU General Public License
along with this program. If not, see <http://www.gnu.org/licenses/>.
'''