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functions4.rs
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68 lines (54 loc) · 2.15 KB
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fn main() {
use std::mem;
let color = "green";
// A closure to print `color` which immediately borrows (`&`) `color` and
// stores the borrow and closure in the `print` variable. It will remain
// borrowed until `print` is used the last time.
//
// `println!` only requires arguments by immutable reference so it doesn't
// impose anything more restrictive.
let print = || println!("`color`: {}", color);
// Call the closure using the borrow.
print();
// `color` can be borrowed immutably again, because the closure only holds
// an immutable reference to `color`.
let _reborrow = &color;
print();
// A move or reborrow is allowed after the final use of `print`
let _color_moved = color;
let mut count = 0;
// A closure to increment `count` could take either `&mut count` or `count`
// but `&mut count` is less restrictive so it takes that. Immediately
// borrows `count`.
//
// A `mut` is required on `inc` because a `&mut` is stored inside. Thus,
// calling the closure mutates the closure which requires a `mut`.
let mut inc = || {
count += 1;
println!("`count`: {}", count);
};
// Call the closure using a mutable borrow.
inc();
// The closure still mutably borrows `count` because it is called later.
// An attempt to reborrow will lead to an error.
// let _reborrow = &count;
// ^ TODO: try uncommenting this line.
inc();
// The closure no longer needs to borrow `&mut count`. Therefore, it is
// possible to reborrow without an error
let _count_reborrowed = &mut count;
// A non-copy type.
let movable = Box::new(3);
// `mem::drop` requires `T` so this must take by value. A copy type
// would copy into the closure leaving the original untouched.
// A non-copy must move and so `movable` immediately moves into
// the closure.
let consume = || {
println!("`movable`: {:?}", movable);
mem::drop(movable);
};
// `consume` consumes the variable so this can only be called once.
consume();
// consume();
// ^ TODO: Try uncommenting this line.
}