-
Notifications
You must be signed in to change notification settings - Fork 0
Expand file tree
/
Copy path431-EncodeN-aryTreeToBinaryTree.go
More file actions
121 lines (102 loc) · 3.46 KB
/
431-EncodeN-aryTreeToBinaryTree.go
File metadata and controls
121 lines (102 loc) · 3.46 KB
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
package main
// 431. Encode N-ary Tree to Binary Tree
// Design an algorithm to encode an N-ary tree into a binary tree and decode the binary tree to get the original N-ary tree.
// An N-ary tree is a rooted tree in which each node has no more than N children.
// Similarly, a binary tree is a rooted tree in which each node has no more than 2 children.
// There is no restriction on how your encode/decode algorithm should work.
// You just need to ensure that an N-ary tree can be encoded to a binary tree and this binary tree can be decoded to the original N-nary tree structure.
// Nary-Tree input serialization is represented in their level order traversal, each group of children is separated by the null value (See following example).
// For example, you may encode the following 3-ary tree to a binary tree in this way:
// <img src="https://assets.leetcode.com/uploads/2018/10/12/narytreebinarytreeexample.png" />
// Input: root = [1,null,3,2,4,null,5,6]
// Note that the above is just an example which might or might not work.
// You do not necessarily need to follow this format, so please be creative and come up with different approaches yourself.
// Example 1:
// Input: root = [1,null,3,2,4,null,5,6]
// Output: [1,null,3,2,4,null,5,6]
// Example 2:
// Input: root = [1,null,2,3,4,5,null,null,6,7,null,8,null,9,10,null,null,11,null,12,null,13,null,null,14]
// Output: [1,null,2,3,4,5,null,null,6,7,null,8,null,9,10,null,null,11,null,12,null,13,null,null,14]
// Example 3:
// Input: root = []
// Output: []
// Constraints:
// The number of nodes in the tree is in the range [0, 10^4].
// 0 <= Node.val <= 10^4
// The height of the n-ary tree is less than or equal to 1000
// Do not use class member/global/static variables to store states. Your encode and decode algorithms should be stateless.
import "fmt"
type Node struct {
Val int
Children []*Node
}
// Definition for a binary tree node.
type TreeNode struct {
Val int
Left *TreeNode
Right *TreeNode
}
/**
* Definition for a Node.
* type Node struct {
* Val int
* Children []*Node
* }
*/
/**
* Definition for a binary tree node.
* type TreeNode struct {
* Val int
* Left *TreeNode
* Right *TreeNode
* }
*/
type Codec struct {
}
func Constructor() *Codec {
return &Codec{}
}
func (this *Codec) encode(root *Node) *TreeNode {
if root == nil {
return nil
}
tree := &TreeNode{ Val: root.Val }
if 0 < len(root.Children) {
tree.Left = this.encode(root.Children[0])
cur := tree.Left
for _, c := range root.Children[1:] {
cur.Right = this.encode(c)
cur = cur.Right
}
}
return tree
}
func (this *Codec) decode(root *TreeNode) *Node {
if root == nil {
return nil
}
node := &Node{Val: root.Val}
cur := root.Left
for cur != nil {
node.Children = append(node.Children, this.decode(cur))
cur = cur.Right
}
return node
}
/**
* Your Codec object will be instantiated and called as such:
* obj := Constructor();
* bst := obj.encode(root);
* ans := obj.decode(bst);
*/
func main() {
// Example 1:
// Input: root = [1,null,3,2,4,null,5,6]
// Output: [1,null,3,2,4,null,5,6]
// Example 2:
// Input: root = [1,null,2,3,4,5,null,null,6,7,null,8,null,9,10,null,null,11,null,12,null,13,null,null,14]
// Output: [1,null,2,3,4,5,null,null,6,7,null,8,null,9,10,null,null,11,null,12,null,13,null,null,14]
// Example 3:
// Input: root = []
// Output: []
}