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searchRange.js
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50 lines (45 loc) · 1.03 KB
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/**
* @param {number[]} nums
* @param {number} target
* @return {number[]}
*/
const searchRange = (nums, target) => {
let min = -1
let max = -1
const findNode = (i = 0) => {
if (nums[i] == null) return
if (nums[i] === target) {
if (min === -1 || i < min) min = i
if (i > max) max = i
}
const left = 2 * i + 1
const right = 2 * i + 2
findNode(left)
findNode(right)
}
findNode()
return [min, max]
}
// binary search solution
const searchRange = (nums, target) => {
let left = 0
let right = nums.length
let mid
const result = [-1, -1]
if (!nums.length) return result
while (left < right) {
mid = parseInt((left + right) / 2)
if (nums[mid] >= target) right = mid
else left = mid + 1
}
if (nums[left] === target) result[0] = left
left = 0
right = nums.length
while (left < right) {
mid = parseInt((left + right) / 2)
if (nums[mid] <= target) left = mid + 1
else right = mid
}
if (nums[right - 1] === target) result[1] = right - 1
return result
}