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Copy pathBinaryTreeLevelOrderTraversal.cpp
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BinaryTreeLevelOrderTraversal.cpp
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110 lines (98 loc) · 2.51 KB
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/**
* Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level).
* For example:
* Given binary tree [3,9,20,null,null,15,7],
* return its level order traversal as:
* [
* [3],
* [9,20],
* [15,7]
* ]
* /
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
//Recursive Approach
class Solution {
public:
vector<int> ans_temp;
void printLevel(TreeNode *root, int level){
if(root==NULL){
return ;
}
if(level==0){
ans_temp.push_back(root->val);
}
printLevel(root->left, level-1);
printLevel(root->right, level-1);
}
int getHeight(TreeNode *root){
if(root==NULL){
return 0;
}
int left = getHeight(root->left) + 1;
int right = getHeight(root->right) + 1;
return left > right ? left : right;
}
vector<vector<int>> levelOrder(TreeNode* root) {
vector<vector<int>> ans;
int h = getHeight(root);
for(int i = 0;i<h;i++){
printLevel(root, i);
ans.push_back(ans_temp);
ans_temp.clear();
}
return ans;
}
};
//Iterative approach.
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<vector<int>> levelOrder(TreeNode* root) {
vector<vector<int>> res;
TreeNode * curr = root;
if(!root){
return res;
}
queue<TreeNode * > q;
vector<int> level;
vector<TreeNode *> next;
q.push(root);
while(!q.empty()){
while(!q.empty()){
next.push_back(q.front());
q.pop();
}
for(int i = 0;i<next.size();i++){
if(next[i]!=NULL){
level.push_back(next[i]->val);
if(next[i]->left!=NULL){
q.push(next[i]->left);
}
if(next[i]->right != NULL){
q.push(next[i]->right);
}
}
}
next.clear();
res.push_back(level);
level.clear();
}
return res;
}
};