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day13.py
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100 lines (76 loc) · 2.05 KB
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from functools import reduce
import numpy as np
from aocd.models import Puzzle
def solve_puzzle_one(minutes, input_array):
next = get_next(input_array, minutes)
index_min = np.argmin(next)
print(input_array[index_min] * (next[index_min] - minutes))
def get_next(input_array, minutes):
next = []
for bus in input_array:
if minutes % bus == 0:
next.append((minutes // bus) * bus)
else:
next.append(((minutes // bus) + 1) * bus)
return next
def chinese_remainder(n, a):
""" https://rosettacode.org/wiki/Chinese_remainder_theorem#Python """
sum = 0
prod = reduce(lambda a, b: a * b, n)
for n_i, a_i in zip(n, a):
p = prod // n_i
sum += a_i * mul_inv(p, n_i) * p
return sum % prod
def mul_inv(a, b):
b0 = b
x0, x1 = 0, 1
if b == 1: return 1
while a > 1:
q = a // b
a, b = b, a % b
x0, x1 = x1 - q * x0, x0
if x1 < 0: x1 += b0
return x1
def solve_puzzle_two(input_array):
remainders = []
modulos = []
for idx, value in enumerate(input_array):
if value == 'x':
continue
remainders.append(len(input_array) - (idx + 1))
modulos.append(int(value))
print(chinese_remainder(modulos, remainders) - len(input_array) + 1)
def parse_input(data):
lines = data.splitlines()
minutes = int(lines[0])
return minutes, [int(bus) for bus in lines[1].split(',') if bus != 'x']
def parse_input2(data):
lines = data.splitlines()
return [bus for bus in lines[1].split(',')]
test_input = """939
7,13,x,x,59,x,31,19
"""
test_input2 = """15
17,x,13,19
"""
test_input3 = """15
67,7,59,61
"""
test_input4 = """15
67,x,7,59,61
"""
test_input5 = """15
67,7,x,59,61
"""
test_input6 = """15
1789,37,47,1889
"""
if __name__ == '__main__':
puzzle = Puzzle(year=2020, day=13)
input = puzzle.input_data
if False:
input = test_input6
minutes, array = parse_input(input)
solve_puzzle_one(minutes, array)
array2 = parse_input2(input)
solve_puzzle_two(array2)