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MinimumCost.cpp
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69 lines (69 loc) · 1.76 KB
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#include <iostream>
#define ll long long int
using namespace std;
ll minCost(ll **ar,int n,int m,ll **dp,int i=0,int j=0){
if (i==n || j==m){
return INT_MAX;
}
if (i==n-1 && j==m-1){
dp[i][j] = ar[i][j];
return dp[i][j];
}
if (dp[i][j]!=-1){
return dp[i][j];
}
dp[i][j] = ar[i][j]+min(minCost(ar,n,m,dp,i+1,j), minCost(ar,n,m,dp,i,j+1));
return dp[i][j];
}
ll minCost2(ll **ar,int n,int m){
ll **dp = new ll*[n+1];
for (int i = 0; i <= n; ++i) {
dp[i] = new ll[m+1];
}
for (int i = 0; i <=n; ++i) {
dp[i][0] = 0;
}
for (int i = 0; i <=m; ++i) {
dp[0][i] = 0;
}
for (int i = 1; i <=n ; ++i) {
for (int j = 1; j <=m ; ++j) {
if (i==1){
dp[i][j] = (dp[i][j-1] + ar[i-1][j-1]);
}else if (j==1){
dp[i][j] = (dp[i-1][j] + ar[i-1][j-1]);
}else {
dp[i][j] = min(dp[i - 1][j], dp[i][j - 1]) + ar[i - 1][j - 1];
}
}
}
return dp[n][m];
}
int main(){
cout<<"Enter the value of n & m:\n";
int n,m;
cin>>n>>m;
ll **ar = new ll* [n];
for (ll i = 0; i < n; ++i) {
ar[i] = new ll[m];
}
cout<<"\nEnter the value of array:\n";
for (ll i = 0; i < n; ++i) {
for (ll j = 0; j < m; ++j) {
cin>>ar[i][j];
}
}
ll **dp = new ll* [n];
for (ll i = 0; i < n; ++i) {
dp[i] = new ll[m];
}
for (ll i = 0; i < n; ++i) {
for (ll j = 0; j < m; ++j) {
dp[i][j] = -1;
}
}
cout<<"Using Top Down Approach:\n";
cout<<"Minimum Cost is : "<<minCost(ar,n,m,dp)<<"\n";
cout<<"Using Bottom Up Approach:\n";
cout<<"Minimum Cost is : "<<minCost2(ar,n,m)<<"\n";
}