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Beautiful_Binary_String.java
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56 lines (49 loc) · 1.81 KB
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import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.function.*;
import java.util.regex.*;
import java.util.stream.*;
import static java.util.stream.Collectors.joining;
import static java.util.stream.Collectors.toList;
class Result
{
/*
* Complete the 'beautifulBinaryString' function below.
*
* The function is expected to return an INTEGER.
* The function accepts STRING b as parameter.
*/
public static int beautifulBinaryString(String b)
{
// Write your code here
String sub = "010"; //substring.
int count=0; //this will count the number of deletions inorder to make a beautiful string.
while(b.contains(sub)) //till the string the substring..
{
int index = b.indexOf(sub); //first index of the substring..
char ch = '1'; //the character with which it will be replaced.
b = b.substring(0,index+2) + ch + b.substring(index+3); //this is for creating a new string..(replacing the new character..)
count++; //count the number of deletions..
}
return count; //return the number of deletions..
}
}
public class Solution
{
public static void main(String[] args) throws IOException
{
BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(System.in));
BufferedWriter bufferedWriter = new BufferedWriter(new FileWriter(System.getenv("OUTPUT_PATH")));
int n = Integer.parseInt(bufferedReader.readLine().trim());
String b = bufferedReader.readLine();
int result = Result.beautifulBinaryString(b);
bufferedWriter.write(String.valueOf(result));
bufferedWriter.newLine();
bufferedReader.close();
bufferedWriter.close();
}
}