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LeetCode33.java
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65 lines (60 loc) · 1.92 KB
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public class LeetCode33 {
public static void main(String[] args) {
// 输入:nums = [4,5,6,7,0,1,2], target = 0
// 输出:4
System.out.println(new Solution33().search(new int[] { 4, 5, 6, 7, 0, 1, 2 },
0));
// 输入:nums = [4,5,6,7,0,1,2], target = 3
// 输出:-1
System.out.println(new Solution33().search(new int[] { 4, 5, 6, 7, 0, 1, 2 },
3));
// 输入:nums = [1], target = 0
// 输出:-1
System.out.println(new Solution33().search(new int[] { 1 }, 0));
// 输入:nums = [1,3,5], target = 3
// 输出:1
System.out.println(new Solution33().search(new int[] { 1, 3, 5 }, 3));
}
}
class Solution33 {
public int search(int[] nums, int target) {
int l = 0;
int r = nums.length - 1;
int mid;
while (l < r) {
// System.out.println(l + " " + r);
mid = (l + r) / 2;
if (nums[mid] > nums[r]) {
l = mid + 1;
} else if (nums[mid] < nums[r]) {
r = mid;
}
}
// System.out.println("l: " + l);
// 此时l是第一个元素(最小元素)
if (l == 0) {
return binarySearch(nums, 0, nums.length - 1, target);
}
if (target < nums[0]) {
return binarySearch(nums, l, nums.length - 1, target);
} else if (target > nums[0]) {
return binarySearch(nums, 0, l - 1, target);
} else {
return 0;
}
}
public int binarySearch(int[] nums, int l, int r, int target) {
int mid;
while (l <= r) {
mid = (l + r) / 2;
if (nums[mid] < target) {
l = mid + 1;
} else if (nums[mid] > target) {
r = mid - 1;
} else {
return mid;
}
}
return -1;
}
}