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LeetCode31.java
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104 lines (92 loc) · 3.17 KB
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import java.util.Arrays;
import util.PrintUtil;
public class LeetCode31 {
public static void main(String[] args) {
int[] nums;
// 输入:nums = [1,2,3]
// 输出:[1,3,2]
nums = new int[] { 1, 2, 3 };
System.out.println(Arrays.toString(nums));
new Solution31().nextPermutation(nums);
System.out.println(Arrays.toString(nums));
PrintUtil.printDivider();
// 输入:nums = [1,3,2]
// 输出:[2,1,3]
nums = new int[] { 1, 3, 2 };
System.out.println(Arrays.toString(nums));
new Solution31().nextPermutation(nums);
System.out.println(Arrays.toString(nums));
PrintUtil.printDivider();
// 输入:nums = [3,2,1]
// 输出:[1,2,3]
nums = new int[] { 3, 2, 1 };
System.out.println(Arrays.toString(nums));
new Solution31().nextPermutation(nums);
System.out.println(Arrays.toString(nums));
PrintUtil.printDivider();
// 输入:nums = [1,1,5]
// 输出:[1,5,1]
nums = new int[] { 1, 1, 5 };
System.out.println(Arrays.toString(nums));
new Solution31().nextPermutation(nums);
System.out.println(Arrays.toString(nums));
PrintUtil.printDivider();
// 输入:nums = [2,3,1]
// 输出:[3,1,2]
nums = new int[] { 2, 3, 1 };
System.out.println(Arrays.toString(nums));
new Solution31().nextPermutation(nums);
System.out.println(Arrays.toString(nums));
PrintUtil.printDivider();
}
}
class Solution31 {
public void nextPermutation(int[] nums) {
if (nums.length <= 1) {
return;
}
if (nums.length == 2) {
swap(nums, 0, 1);
return;
}
// 找到逆序的第一位
int reversed_first = nums.length - 1;
while (reversed_first >= 1) {
if (nums[reversed_first] > nums[reversed_first - 1]) {
break;
}
reversed_first--;
}
if (reversed_first == 0) {
// 如果第一位是0,就整体调换
reverse(nums, 0);
} else {
if (reversed_first == nums.length - 1) {
// 如果第一位是最后一位,就需要一次简单的对掉
swap(nums, reversed_first, reversed_first - 1);
} else {
int reversed_suitable = reversed_first;
while (reversed_suitable < nums.length) {
if (nums[reversed_suitable] > nums[reversed_first - 1]) {
reversed_suitable++;
} else {
break;
}
}
swap(nums, reversed_first - 1, reversed_suitable - 1);
reverse(nums, reversed_first);
}
}
}
private void swap(int[] nums, int i, int j) {
int temp;
temp = nums[i];
nums[i] = nums[j];
nums[j] = temp;
}
private void reverse(int[] nums, int start) {
for (int i = 0; i < (nums.length - start) / 2; i++) {
swap(nums, i + start, nums.length - 1 - i);
}
}
}