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LeetCode210.java
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92 lines (83 loc) · 3.05 KB
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import java.util.ArrayList;
import java.util.Arrays;
import util.PrintUtil;
public class LeetCode210 {
public static void main(String[] args) {
int numCourses;
int[][] prerequisites;
// 输入:numCourses = 2, prerequisites = [[1,0]]
// 输出:[0,1]
// 解释:总共有 2 门课程。要学习课程 1,你需要先完成课程 0。因此,正确的课程顺序为 [0,1] 。
numCourses = 2;
prerequisites = new int[][] { { 1, 0 } };
System.out.println(Arrays.deepToString(prerequisites));
System.out.println(Arrays.toString(new Solution210().findOrder(numCourses, prerequisites)));
PrintUtil.printDivider();
// 输入:numCourses = 4, prerequisites = [[1,0],[2,0],[3,1],[3,2]]
// 输出:[0,2,1,3]
numCourses = 4;
prerequisites = new int[][] { { 1, 0 }, { 2, 0 }, { 3, 1 }, { 3, 2 } };
System.out.println(Arrays.deepToString(prerequisites));
System.out.println(Arrays.toString(new Solution210().findOrder(numCourses, prerequisites)));
PrintUtil.printDivider();
// 输入:numCourses = 1, prerequisites = []
// 输出:[0]
numCourses = 1;
prerequisites = new int[][] {};
System.out.println(Arrays.deepToString(prerequisites));
System.out.println(Arrays.toString(new Solution210().findOrder(numCourses, prerequisites)));
PrintUtil.printDivider();
}
}
class Solution210 {
public ArrayList<ArrayList<Integer>> adjList;
public boolean[] visited;// NOTE: 也可以设置visited范围为0,1,2,分别代表未访问/访问中/访问完成
public boolean[] onStack;
public int[] order; // NOTE: 这里是用数组和指针代替栈
public int index; // NOTE: 用来记录顺序的索引
boolean valid = true;
public int[] findOrder(int numCourses, int[][] prerequisites) {
// 构造有向图
adjList = new ArrayList<ArrayList<Integer>>();
for (int i = 0; i < numCourses; i++) {
adjList.add(new ArrayList<Integer>());
}
for (int i = 0; i < prerequisites.length; i++) {
int end = prerequisites[i][0];
int start = prerequisites[i][1];
adjList.get(start).add(end);
}
visited = new boolean[numCourses];
onStack = new boolean[numCourses];
order = new int[numCourses];
index = numCourses - 1;
for (int u = 0; u < numCourses; u++) {
if (!valid) {
break;
}
if (!visited[u]) {
dfs(u);
}
}
if (valid) {
return order;
} else {
return new int[] {};
}
}
public void dfs(int u) {
visited[u] = true;
onStack[u] = true;
for (int v : adjList.get(u)) {
if (!visited[v]) {
dfs(v);
}
if (onStack[v]) {
valid = false;
return;
}
}
onStack[u] = false;
order[index--] = u;
}
}