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Solution.java
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package LinkedList.No_2_AddTwoNumbers;
import LinkedList.ListNode;
/**
* FileName: Solution
* Author: EdisonLi的家用MacBook Pro
* Date: 2019-01-19 17:28
* Description:
* You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
* <p>
* You may assume the two numbers do not contain any leading zero, except the number 0 itself.
* <p>
* Example:
* <p>
* Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
* Output: 7 -> 0 -> 8
* Explanation: 342 + 465 = 807.
*/
public class Solution {
public ListNode addTwoNumbers(ListNode l1, ListNode l2) {
if (l1 == null || l2 == null) {
return null;
}
Long l1Num = listToLong(l1);
Long l2Num = listToLong(l2);
return longToList(l1Num + l2Num);
}
public Long listToLong(ListNode node) {
long num = 0;
long curr = 1;
while (node != null) {
num = num + node.val * curr;
curr = curr * 10;
node = node.next;
}
return num;
}
public ListNode longToList(long num) {
ListNode node = new ListNode(-1);
node.next = null;
ListNode resNode = node;
resNode.val = (int) (num % 10);
num = num / 10;
while (num > 0) {
ListNode nextCode = new ListNode((int) (num % 10));
nextCode.next = null;
resNode.next = nextCode;
num = num / 10;
resNode = resNode.next;
}
return node;
}
// public ListNode addTwoNumbers1(ListNode l1, ListNode l2) {
// ListNode dummy = new ListNode(-1);
// ListNode cur = dummy;
// int carry = 0;
// while (l1 != null || l2 != null) {
// int d1 = l1 == null ? 0 : l1.val;
// int d2 = l2 == null ? 0 : l2.val;
// int sum = d1 + d2 + carry;
// carry = sum >= 10 ? 1 : 0;
// cur.next = new ListNode(sum % 10);
// cur = cur.next;
// if (l1 != null) l1 = l1.next;
// if (l2 != null) l2 = l2.next;
// }
// if (carry == 1) cur.next = new ListNode(1);
// return dummy.next;
// }
public ListNode addTwoNumbers1(ListNode l1, ListNode l2) {
ListNode dummyHead = new ListNode(-1);
ListNode cur = dummyHead;
int curry = 0;
while (l1 != null || l2 != null) {
int d1 = l1 == null ? 0 : l1.val;
int d2 = l2 == null ? 0 : l2.val;
int sum = d1 + d2 + curry;
curry = sum >= 10 ? 1 : 0;
cur.next = new ListNode(sum % 10);
cur = cur.next;
if (l1 != null) l1 = l1.next;
if (l2 != null) l2 = l2.next;
}
if (curry == 1) cur.next = new ListNode(1);
return dummyHead.next;
}
}